Reasoning — Circular Seating Arrangement

C is the starting point. B is third to the right of C. A is second to the right of B. D is second to the left of E. F is between G and H, so G is between F and D. Thus, D is to the immediate left of G.

Since Q is to the immediate right of P, the order starts as P, Q. S is between Q and T, so the order becomes P, Q, S, T. This leaves R to the immediate left of P, completing the circle as R, P, Q, S, T. Therefore, T is to the immediate left of R.

Let's arrange the people step-by-step: 1. A is to the immediate left of B. (Arrangement: A B _ _ _) Let's place B at position 1 (12 o'clock). Then A is at position 5 (clockwise). (5)A (1)B 2. C is second to the right of A. A is at position 5. Counting two positions to the right of A: 1st right is B (position 1), 2nd right is C (position 2). (5)A (1)B (2)C 3. D is not an immediate neighbour of C. C is at position 2. Its immediate neighbours are B (position 1) and the person at position 3. So, D cannot be at position 1 or 3. Since B is at 1, D cannot be at 3. The remaining people are D and E, and remaining positions are 3 and 4. Since D cannot be at 3, D must be at position 4. This leaves E for position 3. Final arrangement (clockwise from position 1): Position 1: B Position 2: C Position 3: E Position 4: D Position 5: A Now, let's find who is second to the left of D. D is at position 4. Counting two positions to the left of D: 1st left is E (position 3). 2nd left is C (position 2). Therefore, C is second to the left of D.

Let's arrange the people step-by-step: 1. P is to the immediate right of Q. Let Q be at position 1. Then P is at position 2. (1)Q (2)P _ _ _ _ 2. S is second to the left of P. P is at position 2. Counting two positions to the left of P: 1st left is Q (position 1), 2nd left is S (position 6). (1)Q (2)P _ _ _ (6)S 3. R is an immediate neighbour of S and U. This means R is sitting between S and U. So, the sequence is S R U or U R S. S is at position 6. Its neighbours are the person at position 5 and the person at position 1 (Q). Since Q is at 1, R cannot be at 1. So, R must be at position 5, and U at position 4. (1)Q (2)P _ (4)U (5)R (6)S 4. T is not an immediate neighbour of Q. Q is at position 1. Its immediate neighbours are P (position 2) and S (position 6). The only remaining empty position is 3. The only remaining person is T. So, T must be at position 3. (1)Q (2)P (3)T (4)U (5)R (6)S Final arrangement (clockwise from position 1): Position 1: Q Position 2: P Position 3: T Position 4: U Position 5: R Position 6: S Now, let's find who is sitting exactly between P and U when counted from P's right. P is at position 2. Counting from P's right: Immediate right of P is T (position 3). Immediate right of T is U (position 4). So, T is sitting exactly between P and U (P -> T -> U). Therefore, T is sitting exactly between P and U.

Let's arrange the people step-by-step: 1. M is second to the right of P. Let P be at position 1. Then M is at position 3. (1)P (2)_ (3)M (4)_ (5)_ (6)_ 2. Q is to the immediate left of M. M is at position 3. Its immediate left is position 2. So Q is at position 2. (1)P (2)Q (3)M (4)_ (5)_ (6)_ 3. R is not an immediate neighbour of P. P is at position 1. Its immediate neighbours are Q (position 2) and the person at position 6. So, R cannot be at position 6. Remaining people: N, O, R. Remaining positions: 4, 5, 6. Since R cannot be at 6, R must be at 4 or 5. 4. O is second to the left of N. This means N _ O (clockwise order, with one person between N and O). Let's consider the remaining people (N, O, R) and positions (4, 5, 6). If N is at 4, then O would be at 6 (N (4) -> person at 5 -> O (6)). If N is at 5, then O would be at 1 (N (5) -> person at 6 -> O (1)). But P is at 1, so this is not possible. If N is at 6, then O would be at 2 (N (6) -> person at 1 -> O (2)). But Q is at 2, so this is not possible. So, N must be at 4 and O must be at 6. (1)P (2)Q (3)M (4)N (5)_ (6)O Now, R must be at the only remaining position, which is 5. (1)P (2)Q (3)M (4)N (5)R (6)O Let's check all conditions with the final arrangement: Position 1: P Position 2: Q Position 3: M Position 4: N Position 5: R Position 6: O - M is second to the right of P. (P at 1, 1st right Q at 2, 2nd right M at 3. Yes) - Q is to the immediate left of M. (M at 3, immediate left Q at 2. Yes) - R is not an immediate neighbour of P. (P at 1, neighbours Q at 2 and O at 6. R is at 5. Yes) - O is second to the left of N. (N at 4, 1st left M at 3, 2nd left O at 6. Yes) All conditions are satisfied. The arrangement is unique. Now, let's find who is sitting to the immediate right of N. N is at position 4. Its immediate right is R (position 5). Therefore, R is sitting to the immediate right of N. (Wait, I made a mistake in the explanation, O is second to the left of N. N is at 4, 1st left M (3), 2nd left Q (2). My final arrangement check for O is second to the left of N was wrong. Let me re-evaluate step 4.) Re-evaluating step 4: O is second to the left of N. This means N -> X -> O (counter-clockwise, or N -> O with one person between them on N's left). If N is at position X, O is at position X-2 (adjusting for circularity). Remaining people: N, O, R. Remaining positions: 4, 5, 6. - If N is at 4, its 2nd left is 2 (4 -> 3 -> 2). But Q is at 2. So N cannot be at 4. - If N is at 5, its 2nd left is 3 (5 -> 4 -> 3). But M is at 3. So N cannot be at 5. - If N is at 6, its 2nd left is 4 (6 -> 5 -> 4). This is possible! O would be at 4. So, N is at 6, O is at 4. (1)P (2)Q (3)M (4)O (5)_ (6)N Now, R must be at the only remaining position, which is 5. (1)P (2)Q (3)M (4)O (5)R (6)N Final arrangement (clockwise from position 1): Position 1: P Position 2: Q Position 3: M Position 4: O Position 5: R Position 6: N Let's check all conditions with this new final arrangement: - M is second to the right of P. (P at 1, 1st right Q at 2, 2nd right M at 3. Yes) - Q is to the immediate left of M. (M at 3, immediate left Q at 2. Yes) - R is not an immediate neighbour of P. (P at 1, neighbours Q at 2 and N at 6. R is at 5. Yes) - O is second to the left of N. (N at 6, 1st left R at 5, 2nd left O at 4. Yes) All conditions are satisfied. The arrangement is unique. Now, let's find who is sitting to the immediate right of N. N is at position 6. Its immediate right is P (position 1). Therefore, P is sitting to the immediate right of N.

Let's arrange the people step-by-step: 1. H is to the immediate right of F. Let F be at position 1. Then H is at position 2. (1)F (2)H (3)_ (4)_ (5)_ 2. I is second to the left of H. H is at position 2. Counting two positions to the left of H: 1st left is F (position 1), 2nd left is I (position 5). (1)F (2)H (3)_ (4)_ (5)I 3. G is not an immediate neighbour of I. I is at position 5. Its immediate neighbours are F (position 1) and the person at position 4. So, G cannot be at position 4. The remaining people are G and J, and remaining positions are 3 and 4. Since G cannot be at 4, G must be at position 3. This leaves J for position 4. Final arrangement (clockwise from position 1): Position 1: F Position 2: H Position 3: G Position 4: J Position 5: I Now, let's find who is sitting second to the right of G. G is at position 3. Counting two positions to the right of G: 1st right is J (position 4). 2nd right is I (position 5). Therefore, I is sitting second to the right of G.

Let's arrange the people step-by-step: 1. K is second to the right of L. Let L be at position 1. Then K is at position 3. (1)L (2)_ (3)K (4)_ (5)_ (6)_ 2. M is to the immediate left of K. K is at position 3. Its immediate left is position 2. So M is at position 2. (1)L (2)M (3)K (4)_ (5)_ (6)_ 3. P is not an immediate neighbour of L. L is at position 1. Its immediate neighbours are M (position 2) and the person at position 6. So, P cannot be at position 6. Remaining people: N, O, P. Remaining positions: 4, 5, 6. Since P cannot be at 6, P must be at 4 or 5. 4. O is second to the right of N. This means N -> X -> O (clockwise order, with one person between N and O). Let's consider the remaining people (N, O, P) and positions (4, 5, 6). - If N is at 4, then O would be at 6 (N (4) -> person at 5 -> O (6)). This is a possibility. - If N is at 5, then O would be at 1 (N (5) -> person at 6 -> O (1)). But L is at 1, so this is not possible. - If N is at 6, then O would be at 2 (N (6) -> person at 1 -> O (2)). But M is at 2, so this is not possible. So, N must be at 4 and O must be at 6. (1)L (2)M (3)K (4)N (5)_ (6)O Now, P must be at the only remaining position, which is 5. (1)L (2)M (3)K (4)N (5)P (6)O Final arrangement (clockwise from position 1): Position 1: L Position 2: M Position 3: K Position 4: N Position 5: P Position 6: O Let's check all conditions: - K is second to the right of L. (L at 1, 1st right M at 2, 2nd right K at 3. Yes) - M is to the immediate left of K. (K at 3, immediate left M at 2. Yes) - P is not an immediate neighbour of L. (L at 1, neighbours M at 2 and O at 6. P is at 5. Yes) - O is second to the right of N. (N at 4, 1st right P at 5, 2nd right O at 6. Yes) All conditions are satisfied. The arrangement is unique. Now, let's find who is sitting to the immediate right of P. P is at position 5. Its immediate right is O (position 6). Therefore, O is sitting to the immediate right of P.

Let's arrange the people step-by-step: 1. D is to the immediate right of A. Let A be at position 1. Then D is at position 2. (1)A (2)D (3)_ (4)_ (5)_ (6)_ 2. F is second to the left of D. D is at position 2. Counting two positions to the left of D: 1st left is A (position 1), 2nd left is F (position 6). (1)A (2)D (3)_ (4)_ (5)_ (6)F 3. C is an immediate neighbour of F and B. This means C is sitting between F and B. So, the sequence is F C B or B C F. F is at position 6. Its neighbours are the person at position 5 and the person at position 1 (A). Since A is at 1, C cannot be at 1. So, C must be at position 5, and B at position 4. (1)A (2)D (3)_ (4)B (5)C (6)F 4. E is not an immediate neighbour of A. A is at position 1. Its immediate neighbours are D (position 2) and F (position 6). So, E cannot be at position 2 or 6. The only remaining empty position is 3. The only remaining person is E. E must be at position 3. (1)A (2)D (3)E (4)B (5)C (6)F Final arrangement (clockwise from position 1): Position 1: A Position 2: D Position 3: E Position 4: B Position 5: C Position 6: F Let's check all conditions: - D is to the immediate right of A. (A at 1, D at 2. Yes) - F is second to the left of D. (D at 2, 1st left A at 1, 2nd left F at 6. Yes) - C is an immediate neighbour of F and B. (C at 5, neighbours F at 6 and B at 4. Yes) - E is not an immediate neighbour of A. (A at 1, neighbours D at 2 and F at 6. E is at 3. Yes) All conditions are satisfied. The arrangement is unique. Now, let's find who is sitting second to the right of C. C is at position 5. Counting two positions to the right of C: 1st right is F (position 6). 2nd right is A (position 1). Therefore, A is sitting second to the right of C.

Let's arrange the people step-by-step using positions 1-6 clockwise: 1. 'L is to the immediate right of M' means (M L). 4. 'Q is between L and N' means (L Q N) or (N Q L). Let's combine (M L) and (L Q N): This forms a block (M L Q N). Let's place M at position 1: M(1) L(2) Q(3) N(4) _(5) _(6) Remaining people: O, P. Remaining spots: 5, 6. 2. 'N is second to the left of O'. N is at position 4. For N to be second to the left of O, there must be one person between O and N (when moving left from O). If O is at position 6: - Immediate left of O (at 6) is position 5. - Second left of O (at 6) is position 4. This matches N's position. So, O is at position 6. The arrangement becomes: M(1) L(2) Q(3) N(4) _(5) O(6) Remaining person: P. Remaining spot: 5. So, P is at position 5. The complete arrangement (clockwise) is: M L Q N P O. Let's verify all conditions: 1. L is to the immediate right of M: Yes (M -> L). 2. N is second to the left of O: Yes (O -> P -> N). 3. P is not adjacent to M: P is at 5, M is at 1. They are not adjacent. Yes. 4. Q is between L and N: Yes (L Q N). All conditions are satisfied, and the arrangement is unique. Now, answer the question: Who is sitting to the immediate left of P? In the clockwise arrangement M L Q N P O, the person immediately to the left of P is N.