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Quantitative Aptitude — Time, Speed & Distance
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Quantitative Aptitude — Time, Speed & Distance

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Quantitative Aptitude — Time, Speed & Distance — Questions with Answers Open after you finish the quiz — all 25 questions, with answers and explanations.
Q1. A train is moving at a speed of 72 km/h. What is its speed in meters per second?
  1. 10 m/s
  2. 15 m/s
  3. 20 m/s
  4. 25 m/s
Show answer
Answer: C. 20 m/s
To convert km/h to m/s, multiply by 5/18. Speed = 72 * (5/18) = 4 * 5 = 20 m/s.
Q2. A 150-meter long train crosses a pole in 6 seconds. What is the speed of the train?
  1. 10 m/s
  2. 15 m/s
  3. 20 m/s
  4. 25 m/s
Show answer
Answer: D. 25 m/s
When a train crosses a pole, the distance covered is its own length. Speed = Distance / Time = 150 m / 6 s = 25 m/s.
Q3. A train 200 meters long is running at a speed of 60 km/h. How long will it take to cross a platform 300 meters long?
  1. 15 seconds
  2. 20 seconds
  3. 25 seconds
  4. 30 seconds
Show answer
Answer: A. 15 seconds
Total distance to cover = Length of train + Length of platform = 200 m + 300 m = 500 m. Speed = 60 km/h = 60 * (5/18) m/s = 100/3 m/s. Time = Distance / Speed = 500 / (100/3) = 500 * 3 / 100 = 15 seconds.
Q4. Two trains, 120 m and 180 m long, are running in opposite directions on parallel tracks at speeds of 50 km/h and 40 km/h respectively. How long will they take to cross each other?
  1. 10 seconds
  2. 12 seconds
  3. 15 seconds
  4. 18 seconds
Show answer
Answer: B. 12 seconds
Total distance = Sum of lengths = 120 + 180 = 300 m. Relative speed (opposite direction) = Sum of speeds = 50 + 40 = 90 km/h. Convert to m/s: 90 * (5/18) = 5 * 5 = 25 m/s. Time = Distance / Speed = 300 / 25 = 12 seconds.
Q5. A man covers a certain distance at 10 km/h and returns to the starting point at 15 km/h. What is his average speed for the entire journey?
  1. 12 km/h
  2. 12.5 km/h
  3. 13 km/h
  4. 13.5 km/h
Show answer
Answer: A. 12 km/h
For equal distances, average speed = (2 * S1 * S2) / (S1 + S2). Average speed = (2 * 10 * 15) / (10 + 15) = (300) / (25) = 12 km/h.
Q6. A car travels at 40 km/h for 3 hours and then at 60 km/h for 2 hours. What is the average speed of the car for the entire journey?
  1. 45 km/h
  2. 48 km/h
  3. 50 km/h
  4. 52 km/h
Show answer
Answer: B. 48 km/h
Distance 1 = Speed 1 * Time 1 = 40 km/h * 3 h = 120 km. Distance 2 = Speed 2 * Time 2 = 60 km/h * 2 h = 120 km. Total distance = 120 + 120 = 240 km. Total time = 3 + 2 = 5 hours. Average speed = Total distance / Total time = 240 km / 5 h = 48 km/h.
Q7. A train passes a man standing on a platform in 8 seconds and passes the platform (which is 264 meters long) in 20 seconds. What is the length of the train?
  1. 176 m
  2. 180 m
  3. 192 m
  4. 200 m
Show answer
Answer: A. 176 m
Let the length of the train be L meters and its speed be S m/s. When crossing a man, L = S * 8. So, S = L/8. When crossing the platform, L + 264 = S * 20. Substitute S: L + 264 = (L/8) * 20. L + 264 = 2.5L. 264 = 1.5L. L = 264 / 1.5 = 2640 / 15 = 176 meters.
Q8. Two trains of equal length are running on parallel tracks in the same direction at 46 km/h and 36 km/h. The faster train passes the slower train in 36 seconds. What is the length of each train?
  1. 40 m
  2. 50 m
  3. 60 m
  4. 70 m
Show answer
Answer: B. 50 m
Let the length of each train be L meters. Total distance = L + L = 2L. Relative speed (same direction) = 46 - 36 = 10 km/h. Convert to m/s: 10 * (5/18) = 50/18 = 25/9 m/s. Time = 36 seconds. Distance = Speed * Time. 2L = (25/9) * 36. 2L = 25 * 4. 2L = 100. L = 50 meters.
Q9. A man walking at 5 km/h reaches his office 10 minutes late. If he walks at 6 km/h, he reaches 5 minutes early. What is the distance to his office?
  1. 5 km
  2. 6 km
  3. 7.5 km
  4. 8 km
Show answer
Answer: C. 7.5 km
Let the distance be D km and the usual time be T hours. Case 1: D/5 = T + 10/60. Case 2: D/6 = T - 5/60. Subtracting the two equations: D/5 - D/6 = (T + 10/60) - (T - 5/60). D/30 = 15/60. D/30 = 1/4. D = 30/4 = 7.5 km.
Q10. A train covers a distance of 180 km in 4.5 hours. If it travels at 1.5 times its usual speed, how much time will it save?
  1. 1 hour
  2. 1.5 hours
  3. 2 hours
  4. 2.5 hours
Show answer
Answer: B. 1.5 hours
Usual speed = Distance / Time = 180 km / 4.5 h = 40 km/h. New speed = 1.5 * 40 = 60 km/h. New time = Distance / New speed = 180 km / 60 km/h = 3 hours. Time saved = Usual time - New time = 4.5 hours - 3 hours = 1.5 hours.
Q11. The distance between two points A and B is covered in 5 (1/2) hours at a speed of 50 km/hr. If the speed is increased by 5 km/hr, how much time would be saved?
  1. 5 minutes
  2. 15 minutes
  3. 50 minutes
  4. 30 minutes
Show answer
Answer: D. 30 minutes
Distance = 50 × 5.5 = 275 km. New time at 55 km/hr = 275/55 = 5 hours. Time saved = 5.5 - 5 = 0.5 hours = 30 minutes.
Q12. A train having a length of 500 m passes through a tunnel of 1000 m in 1 minute. What is the speed of the train in Km/hr?
  1. 75 Km/hr
  2. 90 Km/hr
  3. 87 Km/hr
  4. 96 Km/hr
Show answer
Answer: B. 90 Km/hr
Total distance = 500+1000 = 1500 m. Time = 60 sec. Speed = 1500/60 = 25 m/s = 25 × 18/5 = 90 km/hr.
Q13. A man walks at a certain speed and reaches his destination which is 6 km in 1 hr 40 minutes. If he runs the same distance in 1 hour 20 minutes what is the difference in speed?
  1. 1 km/hr
  2. 0.9 km/hr
  3. 1.5 km/hr
  4. 1.9 km/hr
Show answer
Answer: B. 0.9 km/hr
Walking speed = 6/(100/60) = 6×60/100 = 3.6 km/hr. Running speed = 6/(80/60) = 6×60/80 = 4.5 km/hr. Difference = 4.5-3.6 = 0.9 km/hr.
Q14. A car travels at the speed of 50 km/hr for the first half of the journey and at the speed of 60 km/hr for the second half of the journey. What is the average speed of the car for the entire journey?
  1. 54.54 km/hr
  2. 36.36 km/hr
  3. 50.5 km/hr
  4. 45.45 km/hr
Show answer
Answer: A. 54.54 km/hr
When equal distances at different speeds: Average = 2V₁V₂/(V₁+V₂) = (2×50×60)/(50+60) = 6000/110 = 54.54 km/hr.
Q15. A train crosses a stationary object in 10 seconds. What is the length of the train if the speed of the train is 25 m/s?
  1. 300 m
  2. 250 m
  3. 320 m
  4. 200 m
Show answer
Answer: B. 250 m
For stationary object: Length of train = Speed × Time = 25 × 10 = 250 m.
Q16. Ali travels a distance of 300 m in 2 minutes and 30 seconds. What is his speed in kmph?
  1. 6.9
  2. 7.1
  3. 7.2
  4. 7.3
Show answer
Answer: C. 7.2
Distance = 300m = 0.3 km. Time = 2.5 min = 2.5/60 hr = 1/24 hr. Speed = 0.3/(1/24) = 0.3 × 24 = 7.2 kmph.
Q17. Ram and Rahim standing at a distance of 680m run towards each other at a speed of 8m/sec and 9m/sec respectively. After how long will they meet?
  1. 17 sec
  2. 24 sec
  3. 40 sec
  4. 36 sec
Show answer
Answer: C. 40 sec
Relative speed (opposite direction) = 8+9 = 17 m/s. Time = Distance/Relative Speed = 680/17 = 40 sec.
Q18. The distance between two places, A and B, is 300 km. Two riders, on scooters start simultaneously from A and B towards each other. The distance between them after 2.5 hrs is 25 km. If the speed of one scooter is 10 km/hr more than the other, find the speed of each scooter in km/hr.
  1. 50 and 60
  2. 30 and 40
  3. 40 and 50
  4. 60 and 70
Show answer
Answer: A. 50 and 60
Distance covered = 300-25 = 275 km. Let speeds be x and (x+10). 2.5x + 2.5(x+10) = 275. 5x+25 = 275, x=50. Speeds = 50 and 60 km/hr.
Q19. A man travelling by bus finds that the bus crosses 35 electric poles in 1 minute and the distance between 2 poles is 50 metres. Find the speed of the bus.
  1. 112 km/hr
  2. 102 km/hr
  3. 110 km/hr
  4. 120 km/hr
Show answer
Answer: B. 102 km/hr
35 poles = 34 gaps × 50m = 1700m. Speed = 1700/60 m/s = 28.33 m/s × 18/5 = 102 km/hr.
Q20. A train running at 90 km/h crosses an electric pole in 18 seconds and a platform in 65 seconds. What is the length of the platform?
  1. 1175 m
  2. 1250 m
  3. 1050 m
  4. 1020 m
Show answer
Answer: A. 1175 m
Train speed = 90 × 5/18 = 25 m/s. Length of train = 25 × 18 = 450m. Length of (train+platform) = 25 × 65 = 1625m. Platform = 1625-450 = 1175m.
Q21. What is the time taken by a 450m long train running at 54 km/hr to cross a man standing on a platform?
  1. 25 seconds
  2. 32 seconds
  3. 28 seconds
  4. 30 seconds
Show answer
Answer: D. 30 seconds
Speed = 54 × 5/18 = 15 m/s. Time = 450/15 = 30 sec.
Q22. A person covers a certain distance at a certain speed. If he increases his speed by 30%, then he takes 15 minutes less to cover the same distance. Find the time taken by him to cover the distance when travelling at his original speed.
  1. 1 hour 12 minutes
  2. 1 hour
  3. 1 hour 05 minutes
  4. 1 hour 10 minutes
Show answer
Answer: C. 1 hour 05 minutes
Let original speed=s, time=t. New speed = 1.3s, new time = (t - 1/4). So 1.3s(t-1/4) = st. 1.3t - 0.325 = t. 0.3t = 0.325, t = 13/12 hr = 65 minutes = 1 hr 5 min.
Q23. A train is travelling at a speed of 84 km/h passes a post in 9 seconds and a platform in 30 seconds. What is the length of the platform?
  1. 500 m
  2. 540 m
  3. 480 m
  4. 490 m
Show answer
Answer: D. 490 m
Speed = 84 × 5/18 = 70/3 m/s. Train length = 70/3 × 9 = 210m. Train+platform = 70/3 × 30 = 700m. Platform = 700-210 = 490m.
Q24. Two persons A and B are travelling towards each other at the speeds of 10 km/h and 14 km/h. The distance between them is 24 km. Find the time taken by them to meet each other.
  1. 1 hour
  2. 2 hours
  3. 3 hours
  4. 4 hours
Show answer
Answer: A. 1 hour
Relative speed = 10+14 = 24 km/h (opposite direction). Time = Distance/Relative speed = 24/24 = 1 hour.
Q25. Walking at 5/6 of her usual speed Anita took 2 minutes more than usual to reach the bus terminus. How long does Anita take to reach the terminus on days that she isn't late?
  1. 8 minutes
  2. 12 minutes
  3. 10 minutes
  4. 9 minutes
Show answer
Answer: C. 10 minutes
Let usual time = t. New time = t+2 at 5/6 speed. So t × (1) = (t+2) × (5/6). 6t = 5t+10. t = 10 minutes.
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