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Quantitative Aptitude — Ratio & Proportion
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Quantitative Aptitude — Ratio & Proportion

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8 mins
Time
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10
Questions
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1
Per Q

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Quantitative Aptitude — Ratio & Proportion — Questions with Answers Open after you finish the quiz — all 10 questions, with answers and explanations.
Q1. If A:B = 3:4 and B:C = 8:9, find A:B:C.
  1. 6:8:9
  2. 3:8:9
  3. 6:4:9
  4. 3:4:9
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Answer: A. 6:8:9
To combine ratios, make the common term (B) equal. A:B = 3:4 = 6:8 (multiply by 2). B:C = 8:9. So, A:B:C = 6:8:9.
Q2. The ratio of two numbers is 5:7. If the sum of the numbers is 144, what is the smaller number?
  1. 84
  2. 60
  3. 72
  4. 50
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Answer: B. 60
Let the numbers be 5x and 7x. Their sum is 5x + 7x = 12x. Given 12x = 144, so x = 12. The smaller number is 5x = 5 * 12 = 60.
Q3. A sum of money is to be distributed among P, Q, and R in the ratio 3:5:7. If R gets Rs. 1200 more than P, what is Q's share?
  1. Rs. 1500
  2. Rs. 2100
  3. Rs. 2500
  4. Rs. 3000
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Answer: C. Rs. 2500
Let the shares be 3x, 5x, and 7x. R gets 7x and P gets 3x. The difference is 7x - 3x = 4x. Given 4x = 1200, so x = 300. Q's share is 5x = 5 * 300 = Rs. 1500.
Q4. If 12 men can complete a work in 20 days, how many men will complete the same work in 15 days?
  1. 15
  2. 18
  3. 20
  4. 16
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Answer: D. 16
This is an inverse proportion problem. (Men1 * Days1) = (Men2 * Days2). So, 12 * 20 = Men2 * 15. Men2 = (12 * 20) / 15 = 240 / 15 = 16 men.
Q5. The present ages of A and B are in the ratio 4:5. After 8 years, their ages will be in the ratio 5:6. What is the present age of A?
  1. 32 years
  2. 40 years
  3. 28 years
  4. 36 years
Show answer
Answer: A. 32 years
Let present ages be 4x and 5x. After 8 years, ages will be (4x+8) and (5x+8). (4x+8)/(5x+8) = 5/6. Cross-multiply: 6(4x+8) = 5(5x+8) => 24x + 48 = 25x + 40 => x = 8. Present age of A = 4x = 4 * 8 = 32 years.
Q6. A mixture contains milk and water in the ratio 5:3. If 8 liters of water are added to the mixture, the ratio of milk to water becomes 1:1. What is the quantity of milk in the mixture?
  1. 30 liters
  2. 40 liters
  3. 20 liters
  4. 25 liters
Show answer
Answer: B. 40 liters
Let the initial quantity of milk be 5x and water be 3x. After adding 8 liters of water, milk is 5x and water is (3x+8). New ratio: 5x / (3x+8) = 1/1. So, 5x = 3x + 8 => 2x = 8 => x = 4. Quantity of milk = 5x = 5 * 4 = 20 liters.
Q7. The ratio of the number of boys to girls in a school is 7:5. If there are 2400 students in the school, how many girls are there?
  1. 1400
  2. 900
  3. 1000
  4. 1200
Show answer
Answer: C. 1000
Total ratio parts = 7 + 5 = 12. Each part represents 2400 / 12 = 200 students. Number of girls = 5 parts = 5 * 200 = 1000.
Q8. Find the mean proportional between 9 and 16.
  1. 14
  2. 13
  3. 12.5
  4. 12
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Answer: D. 12
The mean proportional between two numbers 'a' and 'b' is sqrt(a*b). So, mean proportional = sqrt(9 * 16) = sqrt(144) = 12.
Q9. Two numbers are in the ratio 3:5. If 9 is subtracted from each number, the new ratio becomes 12:23. Find the smaller number.
  1. 33
  2. 55
  3. 27
  4. 45
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Answer: A. 33
Let the numbers be 3x and 5x. After subtracting 9, they become (3x-9) and (5x-9). (3x-9)/(5x-9) = 12/23. Cross-multiply: 23(3x-9) = 12(5x-9) => 69x - 207 = 60x - 108 => 9x = 99 => x = 11. The smaller number is 3x = 3 * 11 = 33.
Q10. A, B, and C started a business by investing Rs. 12000, Rs. 15000, and Rs. 18000 respectively. At the end of the year, they earned a profit of Rs. 9000. What is B's share of the profit?
  1. Rs. 2400
  2. Rs. 3000
  3. Rs. 3600
  4. Rs. 4000
Show answer
Answer: B. Rs. 3000
The ratio of investments is 12000:15000:18000 = 12:15:18 = 4:5:6. Total ratio parts = 4+5+6 = 15. B's share of profit = (5/15) * 9000 = (1/3) * 9000 = Rs. 3000.
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