Q1.
A sum borrowed at 5% per annum simple interest earns an interest which is one-fourth of its principal in x years. Find x.
- 5 years
- 4 years
- 6 years
- 7 years
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Answer: A. 5 years
Given SI = P/4. Using SI = PRT/100, we get P/4 = (P × 5 × x)/100. So 100P = 20Px, hence x = 100/20 = 5 years.
Q2.
What will Rs. 50,000 amount to in 2 years at the rate of 10% per annum, if interest is compounded yearly?
- Rs. 55,000
- Rs. 60,000
- Rs. 60,500
- Rs. 62,500
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Answer: C. Rs. 60,500
A = P(1 + R/100)^n = 50000 × (1 + 10/100)^2 = 50000 × (1.1)^2 = 50000 × 1.21 = 60,500.
Q3.
How long will a sum of money take to double, if it is invested at 10% per annum simple interest?
- 8 years
- 9 years
- 10 years
- 12 years
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Answer: C. 10 years
For money to double, SI = P. So P = (P × 10 × T)/100, giving T = 100/10 = 10 years.
Q4.
What is the ratio of simple interest earned on a certain amount at the rate of 8% per annum for 5 years and that for 10 years?
- 1:2
- 2:3
- 3:4
- 1:3
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Answer: A. 1:2
When Principal (P) and Rate (R) are the same, Simple Interest (SI) is directly proportional to time (T). So the ratio of interests will be the ratio of times: 5 : 10 = 1 : 2.
Q5.
What will be the effective rate of interest if the annual rate is 12% and the interest is compounded on a half-yearly basis?
- 12.18%
- 12.36%
- 12.42%
- 12.50%
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Answer: B. 12.36%
Half-yearly rate becomes 12%/2 = 6%. Effective annual rate = [(1 + 6/100)^2 - 1] × 100 = [(1.06)^2 - 1] × 100 = (1.1236 - 1) × 100 = 12.36%.
Q6.
A certain sum amounts to Rs. 20,000 in 5 years at x% per annum on simple interest. If the rate of simple interest per annum had been (x + 2)%, the amount payable after 5 years would have been Rs. 22,000. Find the sum invested.
- Rs. 18,000
- Rs. 19,000
- Rs. 20,000
- Rs. 21,000
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Answer: C. Rs. 20,000
The extra amount due to 2% higher rate over 5 years = 22000 - 20000 = 2000. So (P × 2 × 5)/100 = 2000, giving 10P/100 = 2000, hence P = 2000 × 100/10 = 20,000.
Q7.
A sum of Rs. 10,000 was invested for a year at 8% per annum interest, compounded half-yearly. What would be the interest payable at the end of the year?
- Rs. 800
- Rs. 816
- Rs. 832
- Rs. 848
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Answer: B. Rs. 816
Half-yearly rate = 8%/2 = 4%, and time = 2 half-years. A = 10000 × (1 + 4/100)^2 = 10000 × (1.04)^2 = 10000 × 1.0816 = 10,816. Interest = 10816 - 10000 = 816.
Q8.
The amount payable on maturity of a certain sum invested for 4 years at a certain rate per annum is Rs. 8,000, and the amount payable on the same sum invested for 6 years at the same rate is Rs. 10,000. If simple interest is offered in both cases, the rate of interest per annum is:
- 20%
- 22.5%
- 25%
- 30%
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Answer: C. 25%
Interest for extra (6-4) = 2 years = 10000 - 8000 = 2000. So SI for 1 year = 2000/2 = 1000. SI for 4 years = 4 × 1000 = 4000. Principal = Amount - SI = 8000 - 4000 = 4000. Now, SI = PRT/100 => 4000 = (4000 × R × 4)/100 => 4000 = 160R, hence R = 4000/160 = 25%.
Q9.
A sum of money at a certain rate of interest when compounded annually becomes Rs. 800 in 2 years and Rs. 880 in 3 years. What is the rate of interest per annum?
- 8%
- 10%
- 12%
- 15%
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Answer: B. 10%
Interest earned during the 3rd year alone = 880 - 800 = 80. This interest is on the amount at the start of the 3rd year, which is 800. So Rate = (Interest / Principal for that year) × 100 = (80/800) × 100 = 10%.
Q10.
A certain sum on compound interest becomes Rs. 48,400 when compounded annually after 2 years and Rs. 53,240 after 3 years. Find the sum.
- Rs. 40,000
- Rs. 42,000
- Rs. 44,000
- Rs. 45,000
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Answer: A. Rs. 40,000
CI in 3rd year = 53240 - 48400 = 4840. Rate = (4840/48400) × 100 = 10%. Now, A = P(1 + R/100)^n => 48400 = P × (1 + 10/100)^2 = P × (1.1)^2 = P × 1.21. So P = 48400 / 1.21 = 40,000.
Q11.
Out of a total sum of Rs. 6,000, Danish invested one part at 8% simple interest per annum and the remaining part at 10% simple interest per annum. If the total interest that accrued to Danish in three years equals Rs. 1,620, what was the sum Danish invested at 8% simple interest per annum?
- Rs. 2,500
- Rs. 3,000
- Rs. 3,500
- Rs. 4,000
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Answer: B. Rs. 3,000
Let the part invested at 8% be x, then the part at 10% is (6000 - x). Total 3-year interest = (x × 8 × 3)/100 + ((6000-x) × 10 × 3)/100 = 1620. This simplifies to 0.24x + 1800 - 0.3x = 1620, so -0.06x = 1620 - 1800 = -180, hence x = 180 / 0.06 = 3,000.
Q12.
The difference between the interest payable on a sum invested for three years at 10% compound interest per annum compounded annually and 10% simple interest per annum for the same period is Rs. 62. What is the value of the sum invested?
- Rs. 1,500
- Rs. 2,000
- Rs. 2,500
- Rs. 3,000
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Answer: B. Rs. 2,000
For 3 years at 10%, CI - SI = P × [(1 + 0.1)^3 - 1 - 3 × 0.1] = P × [1.331 - 1 - 0.3] = P × 0.031. So 62 = 0.031P, giving P = 62 / 0.031 = 2,000.
Q13.
On what sum will the compound interest, at the rate of 10% per annum for 2 years compounded annually, be Rs. 2,100?
- Rs. 9,000
- Rs. 10,000
- Rs. 10,500
- Rs. 11,000
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Answer: B. Rs. 10,000
CI = P[(1 + R/100)^n - 1] = P[(1 + 10/100)^2 - 1] = P[(1.1)^2 - 1] = P[1.21 - 1] = 0.21P. So 2100 = 0.21P, giving P = 2100 / 0.21 = 10,000.
Q14.
A principal amount of Rs. 8,000 borrowed at compound interest is raised to Rs. 9,261 in 3 years. What is the rate of interest?
- 4%
- 5%
- 6%
- 7%
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Answer: B. 5%
A/P = (1 + R/100)^n. So 9261/8000 = (1 + R/100)^3. We know that 9261 = 21^3 and 8000 = 20^3. So (21/20)^3 = (1 + R/100)^3. Taking cube root on both sides: 21/20 = 1 + R/100, hence R/100 = 21/20 - 1 = 1/20, so R = 5%.
Q15.
A invests two equal amounts in two banks giving rates of simple interest as 8% per annum and 12% per annum respectively. At the end of the year, the total interest earned is Rs. 2,000. The amount invested in each bank is:
- Rs. 8,000
- Rs. 9,000
- Rs. 10,000
- Rs. 12,000
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Answer: C. Rs. 10,000
Let each amount be x. Then total interest = (x × 8 × 1)/100 + (x × 12 × 1)/100 = 0.08x + 0.12x = 0.20x. Given total interest = 2000. So 0.20x = 2000, which means x = 2000 / 0.20 = 10,000.