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Quantitative Aptitude — Compound Interest — Questions with Answers
Open after you finish the quiz — all 10 questions,
with answers and explanations.
Q1.
What will be the Compound Interest (CI) on a sum of Rs. 10000 for 2 years at a rate of 10% per annum, compounded annually?
Rs. 2000
Rs. 2100
Rs. 2200
Rs. 2300
Show answer
Answer: B. Rs. 2100
Formula for Amount (A) = P(1 + R/100)^T
Here, Principal (P) = Rs. 10000, Rate (R) = 10% per annum, Time (T) = 2 years.
Step 1: Calculate the Amount (A).
A = 10000(1 + 10/100)^2
A = 10000(1.1)^2
A = 10000 * 1.21
A = Rs. 12100
Step 2: Calculate the Compound Interest (CI).
CI = A - P
CI = 12100 - 10000
CI = Rs. 2100
Q2.
What will be the Amount if Rs. 8000 is invested at 5% per annum Compound Interest for 3 years, compounded annually?
Rs. 9200
Rs. 9261
Rs. 9300
Rs. 9400
Show answer
Answer: B. Rs. 9261
Formula for Amount (A) = P(1 + R/100)^T
Here, Principal (P) = Rs. 8000, Rate (R) = 5% per annum, Time (T) = 3 years.
Step 1: Calculate the Amount (A).
A = 8000(1 + 5/100)^3
A = 8000(1.05)^3
A = 8000 * 1.157625
A = Rs. 9261
Q3.
The difference between Compound Interest (CI) and Simple Interest (SI) on a sum of Rs. 5000 for 2 years at 8% per annum is:
Rs. 24
Rs. 32
Rs. 40
Rs. 48
Show answer
Answer: B. Rs. 32
Formula for the difference between CI and SI for 2 years = P(R/100)^2
Here, Principal (P) = Rs. 5000, Rate (R) = 8% per annum.
Step 1: Calculate the difference.
Difference = 5000 * (8/100)^2
Difference = 5000 * (0.08)^2
Difference = 5000 * 0.0064
Difference = Rs. 32
Q4.
Find the Compound Interest (CI) on Rs. 16000 for 1 year at 10% per annum, compounded half-yearly.
Rs. 1600
Rs. 1620
Rs. 1640
Rs. 1680
Show answer
Answer: C. Rs. 1640
When compounded half-yearly, the rate is halved and time is doubled.
New Rate (R') = R/2 = 10%/2 = 5% per half-year.
New Time (T') = T * 2 = 1 year * 2 = 2 half-years.
Formula for Amount (A) = P(1 + R'/100)^T'
Here, Principal (P) = Rs. 16000.
Step 1: Calculate the Amount (A).
A = 16000(1 + 5/100)^2
A = 16000(1.05)^2
A = 16000 * 1.1025
A = Rs. 17640
Step 2: Calculate the Compound Interest (CI).
CI = A - P
CI = 17640 - 16000
CI = Rs. 1640
Q5.
A certain sum of money yields a Compound Interest of Rs. 1324 in 3 years at 10% per annum, compounded annually. What is the principal sum?
Rs. 3600
Rs. 3800
Rs. 4000
Rs. 4200
Show answer
Answer: C. Rs. 4000
Formula for Compound Interest (CI) = P[(1 + R/100)^T - 1]
Here, CI = Rs. 1324, Rate (R) = 10% per annum, Time (T) = 3 years.
Step 1: Substitute the values into the formula.
1324 = P[(1 + 10/100)^3 - 1]
1324 = P[(1.1)^3 - 1]
1324 = P[1.331 - 1]
1324 = P[0.331]
Step 2: Solve for Principal (P).
P = 1324 / 0.331
P = Rs. 4000
Q6.
At what rate of Compound Interest per annum will a sum of Rs. 10000 amount to Rs. 12100 in 2 years, compounded annually?
8%
9%
10%
11%
Show answer
Answer: C. 10%
Formula for Amount (A) = P(1 + R/100)^T
Here, Amount (A) = Rs. 12100, Principal (P) = Rs. 10000, Time (T) = 2 years.
Step 1: Substitute the values into the formula.
12100 = 10000(1 + R/100)^2
12100/10000 = (1 + R/100)^2
1.21 = (1 + R/100)^2
Step 2: Take the square root of both sides.
sqrt(1.21) = 1 + R/100
1.1 = 1 + R/100
Step 3: Solve for Rate (R).
R/100 = 1.1 - 1
R/100 = 0.1
R = 0.1 * 100
R = 10%
Q7.
What is the difference between Compound Interest (CI) and Simple Interest (SI) on a principal of Rs. 12000 at 10% per annum for 3 years?
Rs. 360
Rs. 372
Rs. 384
Rs. 396
Show answer
Answer: B. Rs. 372
Formula for the difference between CI and SI for 3 years = P(R/100)^2 * (3 + R/100)
Here, Principal (P) = Rs. 12000, Rate (R) = 10% per annum.
Step 1: Calculate the difference.
Difference = 12000 * (10/100)^2 * (3 + 10/100)
Difference = 12000 * (0.1)^2 * (3 + 0.1)
Difference = 12000 * 0.01 * 3.1
Difference = 120 * 3.1
Difference = Rs. 372
Q8.
Find the Compound Interest (CI) on Rs. 20000 for 2 years 6 months at 10% per annum, compounded annually.
Rs. 5000
Rs. 5200
Rs. 5410
Rs. 5500
Show answer
Answer: C. Rs. 5410
For compound interest with fractional time, calculate for full years first, then simple interest for the remaining fraction on the amount.
Here, Principal (P) = Rs. 20000, Rate (R) = 10% per annum, Time (T) = 2 years 6 months.
Step 1: Calculate Amount for 2 full years.
Formula for Amount (A) = P(1 + R/100)^T
A_2years = 20000(1 + 10/100)^2
A_2years = 20000(1.1)^2
A_2years = 20000 * 1.21
A_2years = Rs. 24200
Step 2: Calculate Simple Interest for the remaining 6 months (1/2 year) on A_2years.
Formula for Simple Interest (SI) = (P * R * T) / 100
SI_6months = (24200 * 10 * (6/12)) / 100
SI_6months = (24200 * 10 * 0.5) / 100
SI_6months = 24200 * 5 / 100
SI_6months = Rs. 1210
Step 3: Calculate Total Compound Interest (CI).
Total CI = (A_2years - P) + SI_6months
Total CI = (24200 - 20000) + 1210
Total CI = 4200 + 1210
Total CI = Rs. 5410
Q9.
In how many years will a sum of Rs. 6250 amount to Rs. 7290 at 8% per annum Compound Interest, compounded annually?
1 year
1.5 years
2 years
2.5 years
Show answer
Answer: C. 2 years
Formula for Amount (A) = P(1 + R/100)^T
Here, Amount (A) = Rs. 7290, Principal (P) = Rs. 6250, Rate (R) = 8% per annum.
Step 1: Substitute the values into the formula.
7290 = 6250(1 + 8/100)^T
7290/6250 = (1.08)^T
729/625 = (108/100)^T
729/625 = (27/25)^T
Step 2: Express both sides with the same base.
We know that 27^2 = 729 and 25^2 = 625.
So, (27/25)^2 = (27/25)^T
Step 3: Equate the powers to find Time (T).
T = 2 years
Q10.
Calculate the Compound Interest (CI) on Rs. 16000 for 9 months at 20% per annum, compounded quarterly.
Rs. 2400
Rs. 2480
Rs. 2522
Rs. 2560
Show answer
Answer: C. Rs. 2522
When compounded quarterly, the rate is divided by 4 and time is multiplied by 4.
New Rate (R') = R/4 = 20%/4 = 5% per quarter.
New Time (T') = T * 4 = 9 months = (9/12) years = (3/4) years.
So, T' = (3/4) * 4 = 3 quarters.
Formula for Amount (A) = P(1 + R'/100)^T'
Here, Principal (P) = Rs. 16000.
Step 1: Calculate the Amount (A).
A = 16000(1 + 5/100)^3
A = 16000(1.05)^3
A = 16000 * 1.157625
A = Rs. 18522
Step 2: Calculate the Compound Interest (CI).
CI = A - P
CI = 18522 - 16000
CI = Rs. 2522