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Quantitative Aptitude — Age Calculations — Questions with Answers
Open after you finish the quiz — all 10 questions,
with answers and explanations.
Q1.
The ratio of the ages of A and B is 3:5. If the sum of their ages is 48 years, what is the age of B?
18 years
24 years
36 years
30 years
Show answer
Answer: D. 30 years
Let ages be 3x and 5x. 3x + 5x = 48 => 8x = 48 => x = 6. B's age = 5x = 5 × 6 = 30 years.
Q2.
The present age of a father is 42 years and that of his son is 14 years. In how many years will the father's age be twice the son's age?
10 years
12 years
16 years
14 years
Show answer
Answer: D. 14 years
Let 'x' be the number of years. (42 + x) = 2 × (14 + x) => 42 + x = 28 + 2x => x = 14 years.
Q3.
The average age of 30 students and a teacher is 15 years. If the teacher's age is excluded, the average age of the students becomes 14 years. What is the teacher's age?
40 years
50 years
55 years
45 years
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Answer: D. 45 years
Total age of 31 people = 31 × 15 = 465 years. Total age of 30 students = 30 × 14 = 420 years. Teacher's age = 465 - 420 = 45 years.
Q4.
The sum of the ages of P and Q is 35 years. P is 5 years older than Q. What is the present age of P?
15 years
25 years
20 years
30 years
Show answer
Answer: C. 20 years
Let Q's age be x. P's age = x + 5. x + (x + 5) = 35 => 2x + 5 = 35 => 2x = 30 => x = 15. P's age = 15 + 5 = 20 years.
Q5.
Ram is twice as old as Shyam. Five years ago, Ram was three times as old as Shyam. What is Ram's present age?
10 years
15 years
20 years
25 years
Show answer
Answer: C. 20 years
Let Shyam's present age be x. Ram's present age = 2x. Five years ago: Ram = 2x - 5, Shyam = x - 5. (2x - 5) = 3 × (x - 5) => 2x - 5 = 3x - 15 => x = 10. Ram's present age = 2 × 10 = 20 years.
Q6.
The ratio of the ages of A and B is 3:4. After 5 years, the ratio of their ages will be 4:5. What is the present age of A?
15 years
20 years
25 years
30 years
Show answer
Answer: A. 15 years
Let present ages be 3x and 4x. After 5 years, ages will be 3x + 5 and 4x + 5. (3x + 5) ÷ (4x + 5) = 4 ÷ 5 => 5(3x + 5) = 4(4x + 5) => 15x + 25 = 16x + 20 => x = 5. A's present age = 3x = 3 × 5 = 15 years.
Q7.
The present age of a mother is three times the present age of her daughter. Six years from now, the mother's age will be two times the daughter's age. What is the present age of the daughter?
6 years
8 years
10 years
12 years
Show answer
Answer: A. 6 years
Let daughter's present age be x. Mother's present age = 3x. After 6 years: Mother = 3x + 6, Daughter = x + 6. (3x + 6) = 2 × (x + 6) => 3x + 6 = 2x + 12 => x = 6 years.
Q8.
The product of the ages of two brothers is 192. If the elder brother is 4 years older than the younger brother, what is the age of the younger brother?
12 years
14 years
16 years
18 years
Show answer
Answer: A. 12 years
Let younger brother's age be x. Elder brother's age = x + 4. x × (x + 4) = 192 => x² + 4x - 192 = 0. (x + 16)(x - 12) = 0. Since age cannot be negative, x = 12.
Q9.
A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of the son?
20 years
22 years
24 years
26 years
Show answer
Answer: B. 22 years
Let son's present age be x. Man's present age = x + 24. In two years: Man = x + 24 + 2 = x + 26, Son = x + 2. (x + 26) = 2 × (x + 2) => x + 26 = 2x + 4 => x = 22 years.
Q10.
The sum of the ages of a father and his son is 60 years. Six years ago, the father's age was five times the age of the son. What is the present age of the son?
12 years
14 years
16 years
18 years
Show answer
Answer: B. 14 years
Let father's present age be F and son's present age be S. F + S = 60. Six years ago: Father = F - 6, Son = S - 6. (F - 6) = 5 × (S - 6) => F - 6 = 5S - 30 => F = 5S - 24. Substitute F in the first equation: (5S - 24) + S = 60 => 6S - 24 = 60 => 6S = 84 => S = 14 years.
